Question

Help me!!!!! please

Answer 1

C

Explanation:

Cost in location A:
`2n-4-2n^2`

Cost in location B:
`(5)/(4)n-(6)/(5)n^2-(11)/(3)`

Combined cost:
`(2n-4-2n^2)+\left((5)/(4)n-(6)/(5)n^2-(11)/(3)\right)`

Add these two polynomials. Combine the like terms:

`\left(2n+(5)/(4)n\right)+\left(-2n^2-(6)/(5)n^2\right)+\left(-4-(11)/(3)\right)\\ \\=(13)/(4)n-(16)/(5)n^2-(23)/(3)\\ \\=-(16)/(5)n^2+(13)/(4)n-(23)/(3)`