Answer:
b) 0.025
Explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The proportion of adults with scores above 130 is closest to
This proportion is 1 subtracted by the pvalue of Z when X = 130. So



has a pvalue of 0.9772
1 - 0.9772 = 0.0228
Closest to 0.025
So the correct answer is:
b) 0.025