Answer:
H2(g) + I2(g) → 2HI(g)
Step-by-step explanation:
Step 1: Data given
hydrogen gas = H2(g)
iodine gas = I2(g)
hydrogen iodide = HI(g)
Step 2: The unbalanced equation
H2(g) + I2(g) → HI(g)
Step 3: Balancing the equation
On theleft side we have 2x H (in H2), On the right side we have 1x H (in HI)
To balance the amount of H on both sides we have to multiply HI on the right by 2
By multiplying HI by 2, the amount of O on both sides is also equal. The equation is balanced.
H2(g) + I2(g) → 2HI(g)