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One vegetable warehouse had 210 tons of potatoes, another one has 180 tons. 90 tons of potatoes were delivered to the first and 120 tons to the second warehouse every day. In how many days will the first warehouse have 1.2 times less potatoes than the second warehouse

User Lavinio
by
3.6k points

2 Answers

4 votes

Answer:

Explanation:

Warehouse 1:

Mass of potatoes = 210 tons

Day 1

90x + 210 tons

Warehouse 2:

Mass of potatoes = 120 tons

Day 1

120x + 210 tons

Where x is the number of days

180 + 120x = 1.2 (210 + 90n)

180 + 120x = 252 + 108x

120x - 108x = 252 - 180

12x = 72

x = 6.

User Ickyrr
by
4.2k points
3 votes

Answer:

6days

Step-by-step explanation

Let's make an equation from this expression.

From the number of potatoes at the first warehouse after x days is:

y = 210 + 90x .............. 1

From the number of potatoes at the second warehouse after x days is:

y = 180 + 120x .............. 2

First warehouse having 1.2times

y = ( 210 + 90x ) × 1.2

y = 252 +108x ................... 3

Now, equate 2 and 3

252 + 108x = 180 + 120x

252 - 180 = 120x - 108x

72 = 12x

x = 72/12

x = 6

Now, substitute 6 into equation 1 and 2

From 1 , y = 210 + 90x

y = 210 + 90 ×6

y = 210 + 540

y = 750

From equation 2

y = 180 + 120x

y = 180 + 120×6

y = 180 + 720

y = 900

Recall that equation 1 was to be 1.2times

From the answer in equation 1

y =750

y = 750 × 1.2

y = 900

Hence, the answer is correct.

User Brian Riley
by
4.7k points