Question

A 28.5 gram piece of iron is added to a graduated cylinder containing 45.5 mL of water. The water in the cylinder rises to the 49.1 mark. Calculate the density of the iron piece.

Answer 1

7.92 .g . mL^-1

Step-by-step explanation:

Data provided in the question

Water liters = 45.5 mL

Pace of iron = 28.5 gram

Rise in the water in the cylinder = 49.1 mark

So by considering the above information

As we know that

`Density = (Mass)/(Volume)`

where,

Mass = 28.5 gram

Volume = 49.1 - 45.5

= 3.6 mL

So, the density is

`Density = (28.5)/(3.6)`

= 7.92 .g . mL^-1

Basically we use the density formula by dividing the mass with the volume