Answer:
0.248 m/s
Step-by-step explanation:
Using the Law Conservation of Linear Momentum
m₁v₁+m₂v₂=(m₁+m₂)V
Where:
m₁= mass of first train
m₂=mass of second train
v₁= velocity of first train
v₂ = Velocity of Second Train
V=Final Velocity after Collision
m₁= 275000 kg
m₂=55000 kg
v₁= 0.325 m/s
v₂ = -0.135 m/s
m₁v₁+m₂v₂=(m₁+m₂)V
(275000X0.325)+(55000X-0.135) = (275000+55000)V
89375-7425=330000V
81950=330000V
V= 81950/330000= 0.2483 m/s.
The Final Velocity, V of the trains after collision is 0.2483 m/s