Question

What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 3? Amplitude = 4; period = π; phase shift: x equals pi over two Amplitude = −4; period = 2π; phase shift: x equals pi over two Amplitude = 4; period = π; phase shift: x equals negative pi over two Amplitude = −4; period = 2π; phase shift: x equals negative pi over two

Answer 1

c. Amplitude = 4; period = π; phase shift: x equals negative pi over two

Explanation:

Answer 2

The correct option is option (c)

Therefore amplitude = 4, period= π and
`\textrm{phase shift}=(-\pi)/(2)`

Explanation:

Amplitude: The amplitude of a wave is a maximum displacement of a particle from its rest position

Period: The ratio of wavelength to the velocity.

Phase shift: The phase shift represents the amount a wave has shifted horizontally from the the usual position.

The equation of a wave is

f(x) = a sin(bx - c)+d

Where

amplitude = |a|

`Period= (2\pi)/(|b|)`

`\textrm{phase shift} = (c)/(b)`

Given equation of wave is

f(x) = -4sin (2x + π) -3

Here a=-4, b=2, c = -π, d = -3

Amplitude = |-4| = 4

`Period = \frac {2 \pi}= \pi`

`\textrm{phase shift}=(-\pi)/(2)`

Therefore amplitude = 4, period= π and
`\textrm{phase shift}=(-\pi)/(2)`