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A box is given a push so that it slides across the floor. how far will it go given that the How far will it go, given that the coefficient of kinetic friction is 0.13 and the push imparts an initial speed of 3.5 m/s

User Jeff Noel
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1 Answer

3 votes

Answer:

4.808m

Step-by-step explanation:

Force is given as:

F = ma

Since the force is a frictional force,

Fr = F

Fr = ma

Frictional force, Fr, is given as:

-umg = ma

a = -ug = -0.13 * 9.8 = -1.274 m/s²

Using one of the equations of motion, we can find the distance:

v² = u² + 2as

Since the box comes to a halt, v = 0m/s:

0 = u² + 2as

s = -u²/2a

s = -(-3.5²)/(2 * 1.274) = 4.808m

User Haomin
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