Question

A technician wraps wire around a tube of length 38 cm having a diameter of 8.3 cm. When the windings are evenly spread over the full length of the tube, the result is a solenoid containing 555 turns of wire.(a) Find the inductance of this solenoid.

Answer 1

The inductance of this solenoid is 5.51 mH.

Step-by-step explanation:

Given that,

length of the tube, l = 38 cm = 0.38 m

Diameter of the tube, d = 8.3 cm

Radius of the tube, r = 4.15 cm

The number of turns, N = 555

We need to find the inductance of this solenoid. It is given by the formula as :

`L=(\mu N^2A)/(l)\\\\L=(4\pi * 10^(-7)* 555^2* \pi * (4.15* 10^(-2))^2)/(0.38)\\\\L=0.00551\ H\\\\L=5.51\ mH`

So, the inductance of this solenoid is 5.51 mH. Hence, this is the required solution.