Question

Write an equation of the line that is parallel to the given line and that passes through the given point

3x + 2y = 5; (2,6)
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A y +6 = -(x + 2)
y-6 = - (x - 2)
Cy-2 - - 3 (x+6)
Dy6=2(x + 2)
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Answer 1

Option B:

Equation of a line is

`$y-6=(-3)/(2) (x-2)`

Solution:

Equation of a parallel line:

3x + 2y = 5

2y = –3x + 5

`$y=(-3x)/(2)+(5)/(2)`

Slope of this line,
`m_1=(-3)/(2)`

If two lines are parallel, then slopes of their lines are equal.

`m_1=m_2`

`m_2=(-3)/(2)`

The line passes through the point (2, 6)

Point-slope formula:

`y-y_1=m(x-x_1)`

`$y-6=(-3)/(2) (x-2)`

This is the equation of the line.

Option B is the correct answer.