Answer:
a) double result = initialValue;
initialValue = initialValue * multiplier;
return result;
Step-by-step explanation:
The next method will have the above code snippet as it body.
First, the value of initialValue is assigned to result. Next, the initialValue is re-calculated by assigning the value of multiplying the initialValue and multiplier to it. Lastly, the value of result is returned.
Therefore, when the next method is called, the value of result is returned.