Answer:
In a closed container with a fixed volume, when the temperature of a gas doubles, the pressure of the gas is also double.
Step-by-step explanation:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Here P₁ is the initial pressure of a gas at temperature T₁ when its temperature change to T₂ its pressure also changes and this is change is directly related to each other.
Consider the following data:
Initial pressure = 13.0 atm
Initial temperature = 293 K
Final temperature = 586 K
Final pressure = ?
Now we will put the values in formula:
13.0 atm / 293 K = P₂/313 K
P₂ = 13.0 atm × 586 K / 293 K
P₂ = 7618 atm. K /293 K
P₂ = 26 atm