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The gas left in a used aerosol can is at a pressure of 103 kPa at 25.0 °C. If the can heats up to 50.0 °C, what is the pressure of the gas inside the can, assuming the volume of the can is constant? A. 112 kPa B. 211 kPa C. 415 kPa D. 541 kPa

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A.

112 kPa

Step-by-step explanation:

We’ll use the combined gas law equation;

P₁V₁/T₁ = P₂V₂/T₂

Because the volume of the gas remains the same, then the V₁ and V₂ cancel out leaving us with;

P₁/T₁ = P₂/T₂

We can now replace the variables with the values given in the question. Remember to convert the temperatures to Kelvin;

25 degrees C = 298.15 K

50 degrees C = 323.15 K

103/298.15 = P₂/323.15

103/298.15 * 323.15 = P₂

111.63659 = P₂

= 112 kPa

User Randy Zwitch
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