Answer:
Step-by-step explanation:
Energy stored in spring = 1/2 k x²
80 = 1/2 x k .2²
k = 4000 N /m
Required force = k x
= 4000 x .2
=800 N
b )
Additional work done
= difference in stored elastic energy
= 1/2 k ( x₂² - x₁² )
= .5 x 4000 ( .4² - .2² )
= 240 J