Question

A chemist prepares a solution of potassium permanganate (KMnO 4)by measuring out 4.6 mu mol of potassium permanganate into a 300. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mmol/L of the chemist's potassium permanganate solution. Round your answer to 2significant digits.

Answer 1

Answer: The concentration of potassium permanganate solution is 0.015 mM

Step-by-step explanation:

To calculate the molarity of solution, we use the equation:

`\text{Milli molarity of the solution}=\frac{\text{Milli moles of solute}* 1000}{\text{Volume of solution (in mL)}}`

We are given:

Moles of solute =
`4.6\mu mol=4.6* 10^(-3)mmol` (Conversion factor:
`1mmol=1000\mu moles`

Volume of solution = 300 mL

Putting values in above equation, we get:

`\text{Milli molarity of the solution}=(4.6* 10^(-3)* 1000)/(300)\\\\\text{Milli molarity of the solution}=0.015mM`

Hence, the concentration of potassium permanganate solution is 0.015 mM