Question

Write the equilibrium‑constant expression for the reaction

A(s)+3B(l)↽−−⇀2C(aq)+D(aq)
in terms of [A], [B], [C], and [D], as needed.

Note that Kc, which is sometimes symbolized as Keq, denotes that the equilibrium constant is expressed using molar concentrations. For this question, Kc means the same thing as Keq.

Kc=

Answer 1

The answer to your question is Kc = Keq = [C]²[D]

Step-by-step explanation:

Balanced chemical reaction

A (s) + 3B (l) ⇔ 2C (aq) + D (aq)

Kc = Keq =
`([C]^(2) [D])/([A][B]^(3))`

But, remember that reactants or products in liquid or solid state must not be considered.

So, A and B must not be considered.

And the Equilibrium constant is:

Kc = Keq = [C]²[D]