Question

A game board has 9 cards, and 3 say WIN. Michal picks 2 cards without replacing the first What is the probability that neither say WIN?

Answer 1

since there are 8 cards, and 2 say WIN, 6 of the 8 cards don't say WIN. You can express this as a ratio of 6:8 which equals 3:4, so the probability that neither says win is 75%.

Explanation:

Answer 2

The probability that neither say WIN is 5/12 when Michal picks 2 cards without replacing the first

How to determine the probability that neither say WIN?

From the question, we have the following parameters that can be used in our computation:

Cards = 9

Win = 3

This means that

No win = 9 - 3

No win = 6

The probability that neither say WIN is then calculated as

P(Neither) = P(No win 1) ( P(No win 2)

Given that the cards are not replaced, we have

P(Neither) = 6/9 * 5/8

Evaluate

P(Neither) = 5/12

Hence, the probability that neither say WIN is 5/12