Question

The LR5 is the specialist submarine for underwater rescue. The average density of seawater is 1028 kg/ m3.

i. Calculate the increase in pressure as LR5 descends from the surface to a depth of 700m.(g=10m/s2 )

Answer 1

P = 7196 [kPa]

Step-by-step explanation:

We can solve this problem using the expression that defines the pressure depending on the height of water column.

P = dens*g*h

where:

dens = 1028 [kg/m^3]

g = 10 [m/s^2]

h = 700 [m]

Therefore:

P = 1028*10*700

P = 7196000 [Pa]

P = 7196 [kPa]