Question

What is the result of the following code?double[] values = new double[4];double sum = 0.0;for (int i = 1; i <= 4; i++) { sum += values[i];}System.out.println(sum);

Answer 1

The following code as it is results in an array out of bound exception.

Step-by-step explanation:

The reason for this exception is that you tried to access index 4 for an array of length four, because Arrays are indexed from zero, the last element in an array of length 4, will be at index 3 (i.e. 0,1,2,3)

To fix this change for (int i = 1; i <= 4; i++) to for (int i = 0; i < 4; i++).

In this way you code compiles and returns the sum of all elements in the array. Since this array is only created and empty, it outputs 0.0