Answer:
The force applied on one wheel during braking = 6.8 lb
Step-by-step explanation:
Area of the piston (A) = 0.4
![in^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/14wtb8chah0f7lgf6upas1c1xqmgud4svd.png)
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) =
![(F)/(A)](https://img.qammunity.org/2021/formulas/physics/college/vb14uihydmkezo9bld81mruf3zfhe0tjdm.png)
⇒ P =
![(6.4)/(0.4)](https://img.qammunity.org/2021/formulas/physics/college/q3npr6u1edprrh4apd0a3nhtfx0hx790q4.png)
⇒ P = 16
![(lb)/(in^(2) )](https://img.qammunity.org/2021/formulas/physics/college/t9taemapxe6lv8qsu4witugeeaz279my54.png)
This is the pressure inside the cylinder.
Let force applied on the brake pad =
![F_(1)](https://img.qammunity.org/2021/formulas/physics/college/838hdogd3g031qylryk5exeyr3t6vwj2ek.png)
Area of the brake pad (
)= 1.7
![in^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/14wtb8chah0f7lgf6upas1c1xqmgud4svd.png)
Thus the pressure on the brake pad (
) =
![(F_(1) )/(A_(1) )](https://img.qammunity.org/2021/formulas/physics/college/qagrz690jo6ra5ddhfe6bycg6m34c05u1u.png)
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P =
![P_(1)](https://img.qammunity.org/2021/formulas/physics/college/fg63ciaigdtjawsbt9oyq60lpv8avoc42c.png)
⇒ 16 =
![(F_(1) )/(A_(1) )](https://img.qammunity.org/2021/formulas/physics/college/qagrz690jo6ra5ddhfe6bycg6m34c05u1u.png)
⇒
= 16 ×
![A_(1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/t371wevgug7fcam1wn27poei03ppy4vp6a.png)
Put the value of
we get
⇒
= 16 × 1.7
⇒
= 27.2 lb
This the total force applied during braking.
The force applied on one wheel =
=
= 6.8 lb
⇒ The force applied on one wheel during braking.