Answer:
51%.
Explanation:
If we have that the probability when at least one wins is 0.3, it means that the probability that none wins would be:
1 - 0.3 = 0.7 would be the probability of not winning any of the first two games, how are two games and are independent events, the probability of not winning any of the 4 games would be:
(0.7) * (0.7) = 0.49
Therefore, the probability of winning at least one game, would be the complement of not winning any, that is:
1 - 0.49 = 0.51
Which means that the probability of winning at least 1 of the four game is 51%.