Question

What is an equation of the line that passes
through the points (3, 3) and (6, -1)?

Answer 1

Explanation:

ghanami

Answer:

Step-by-step explanation:

Hello : let A(3,3) B(6,-1)

the slope is : (YB - YA)/(XB -XA)

(-1-3)/(6-3) = -4/3

an equation is the line is : y = ax+b a is a slope

y = (-4/3)x+b

but this line passes by (6;-1)

so : -1 = (-4/3)(6)+b

b = 7

the equation is : y = (-4/3)x+7

Answer 2

y=-4/3x+7

Explanation:

m=(y2-y1)/(x2-x1)

m=(-1-3)/(6-3)

m=-4/3

y-y1=m(x-x1)

y-3=-4/3(x-3)

y=-4/3x+12/3+3

y=-4/3x+4+3

y=-4/3x+7