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Binh solved this system of equations by graphing. Line 1: y = negative one-half x minus three-halves. Line 2: y = x minus 3. Binh’s Graph On a coordinate plane, a line with equation y = x minus 3 goes through (negative 3, 0) and (0, 3). A line with equation y = negative one-half x minus three-halves goes through (negative 3, 0) and (1, negative 2). Binh says the point of intersection is (0, –3). Which statements identify the errors Binh made? Check all that apply.

Binh listed the coordinates in the wrong order when describing the point of intersection on his graph.
Binh should have graphed the y-intercept of y = x minus 3 at (0, negative 3).
Binh should have graphed the y-intercept of y = x minus 3 at (0, 1).
Binh should have graphed the y-intercept of y = negative one-half x minus three-halves at (0, negative one-half).
Binh should have found the point of intersection to be (1, negative 2).

User Zima
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2 Answers

2 votes

Final answer:

Binh made mistakes in graphing the y-intercepts and identifying the point of intersection. The correct y-intercept for y = x - 3 is (0, -3), and for y = -1/2x - 3/2, it is (0, -3/2). The correct point of intersection for the two lines is (1, -2), not (0, -3).

Step-by-step explanation:

To determine the errors in Binh's graphing of the system of equations, let's analyze each statement:






Looking at each equation:


  1. For y = x minus 3, the y-intercept occurs when x=0, so y = 0 - 3 = -3. The y-intercept should be (0, -3), not (0, 3) as Binh graphed.

  2. For y = -1/2x - 3/2, when x=0, y = -3/2. So the correct y-intercept is (0, -3/2), not (0, -1/2).

To find the point of intersection, we would set the two equations equal to each other and solve for x:

x - 3 = -1/2x - 3/2

Multiplying through by 2 to clear fractions, we get:

2x - 6 = -x - 3

3x = 3

x = 1

Plugging x back into either original equation gives y = -2. Therefore, the correct point of intersection is indeed (1, -2), not (0, -3) as Binh claimed.

User Marc Estrada
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5.6k points
1 vote

Answer:

It's the first, second, AND last option. The guy above me was right but he was supposed to add the first option too :)

User GmonC
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5.7k points