Question

"A hydraulic system is used to lift a" 51 kg "motor in a garage. If the motor sits on a piston of area" 0.25 m2, "and a force is applied to a piston of area" 84 cm2, "what is the minimum force that must be applied to lift the motor in units of N?"

Answer 1

Step-by-step explanation:

Given

mass of motor
`m=51\ kg`

Area of piston
`A_1=0.25\ m^2`

Area of Piston 2 is
`A_2=84\ cm^2`

Weight of motor
`F_1=m\cdot g=51* 9.8`

`F_1=499.8\ N`

If
`F_2` is the force applied on the 2 nd piston

According Pascal law Pressure at both the ends are equal

`(F_1)/(A_1)=(F_2)/(A_2)`

`(499.8)/(0.25)=(F_2)/(84)`

`F_2=167.93\ kN`

`F_2=167.93* 10^3\ N`