Answer:
2975 foot
Explanation:
Let the tower be BC as shown in the diagram.
The distance from a point A on the level ground to the base B of the tower is 5280 feet.
We want to determine the height BC of the tower.
Using trigonometry
Tan θ =Opposite/Adjacent
Tan 29.4°=BC/5280
BC= 5280 X Tan 29.4°
=2975.12709969007
The height of the tower =2975 foot(to the nearest foot)