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A slot machine has 3 dials. Each dial has 30 positions, one which is jackpot, to win jackpot all 3 dials must be in the jackpot position. Assuming each play spins the dials and stops each independently and randomly, what are the odds of one play winning the jackpot?

User Yevgen
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2 Answers

1 vote

Answer: D)1/(30*30*30)=1/27000=0.00003 OR 0.003%

A) 1/20=0.30 OR 3%

B) 3/(30+30+30)=3/90=0.33 OR 33%

C) 3/(30+30+30)=3/27000=0.0001 OR 0.01%

D) 1/(30*30*30)=1/27000=0.00003 OR 0.003%

User Sunil Mishra
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4.7k points
4 votes

Answer:

27000

Explanation:

30×30×30

User Vineethbc
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