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A 0.03 in.diameter glass tube is inserted into SAE 30 oilat 60°F. The contact angle (i.e., the angle a liquid forms in contact with a solid) of oilwith a glass surface is 22°. Determine the capillary rise of gasolinein the tube

User Cyberduck
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Answer:

The value of capillary rise in the tube = 0.0363 cm

Step-by-step explanation:

Diameter of the glass tube = 0.03 meter

Contact angle = 22 degree

We know that the capillary rise (h) in the tube is given by the formula =

h = (2 α cos β) / (d g R )

⇒ d = density of gasoline = 749 kg /
m^(3)

β = 22 degree

R = radius of the tube = 0.015 m

α = surface tension of gasoline = 0.0216 N / m

cos 22 = 0.927

Put all the values in the above formula we get

⇒ h = (2 × 0.0216 × 0.927) / (749 × 9.81 × 0.015)

h = 0.0363 cm

This is the value of capillary rise in the tube.

User Odomontois
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