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a rocket is shot at 32.5 m/s at a 28.8 angle. and hits a log on flat ground. how far away was the log?

User JohnKlehm
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1 Answer

10 votes

Answer:

Let’s assume that the rocket engine turned off at velocity at the level of the log, becoming a passive projectile. Let us also assume negligible air drag. Then range is:

=2sin2=32.52sin57.6∘9.81

= 90.91 metres

User Andrey Baryshnikov
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