Question

The total mechanical energy of a system is equally divided between kinetic energy and potential energy. can never be negative. is constant only if conservative forces act. is either all kinetic energy or all potential energy, at any one instant. is constant only if nonconservative forces act. A skier, of mass 60. kg, pushes off the top of a frictionless hill with an initial speed of 4.0 m/s. How fast will she be moving after dropping 10. m in elevation? 15. m/s 0.15 km/s 0.20 km/s 49. m/s 10. m/s In an inelastic collision, the final total momentum is less than the initial momentum. the same as the initial momentum. insufficient information to answer more than the initial momentum. A handball of mass 0.10 kg, traveling horizontally at 25. m/s, strikes a wall and rebounds at 19. m/s. What is the change in the momentum of the ball? 1.2 N-s 72 N-s 5.4 N-S 1.8N-s 4.4 N-s Car A (mass = 1000 kg) moves to the right along a level, straight road at a speed of 6.0 m/s. It collides directly with car B (mass = 200 kg) in a completely inelastic collision. What is the momentum after the collision if car B was initially at rest? 10. KN-s to the right zero 6.0 KN-s to the right 8.0 KN-s to the left 2.0 KN-s to the right

Answer 1

The skier will be moving at 15 m/s after dropping 10 m in elevation. The change in momentum of the ball is 4.4 N-s. The momentum after the collision if car B was initially at rest is 2.0 KN-s to the right.

Step-by-step explanation:

The total mechanical energy of a system is constant only if conservative forces act. In an inelastic collision, the final total momentum is less than the initial momentum. The change in momentum of an object can be calculated by multiplying the mass of the object by the change in velocity.

1. After dropping 10. m in elevation, the skier will be moving at 15. m/s
2. The change in momentum of the ball is 4.4 N-s
3. The momentum after the collision if car B was initially at rest is 2.0 KN-s to the right

Answer 2

1- is constant only if conservative forces act

2- 60*9.8*10+0.5*60*4^2=0.5*60*v^2

v=14.56=15 m/s

3- B (Momentum is conserved)

4- Change in momentum= m(v-u) = 0.10(19--25)=4.4 Ns

5- 1000*6+0 = 6000 KN Momentum before to the right, So final momentum should also be same.

Step-by-step explanation:

5 questions are in 1 question all of them are answered.