Step-by-step explanation:
The given data is as follows.
q = 9.0 pC =
(as 1 pC =
)
t = 0.47 ms =
(as 1 ms =
)
As we know that relation between charge and current is as follows.
I =
![(q)/(t)](https://img.qammunity.org/2021/formulas/physics/college/wr2yay4japr5a1gu6kjf4kncack1529k2m.png)
Putting the given values into the above formula as follows.
I =
![(q)/(t)](https://img.qammunity.org/2021/formulas/physics/college/wr2yay4japr5a1gu6kjf4kncack1529k2m.png)
=
![(9 * 10^(-12) C)/(0.47 * 10^(-3) s)](https://img.qammunity.org/2021/formulas/physics/college/453j0eu2r16uoxocc2mc34nlsxv7ipm7in.png)
=
![19.14 * 10^(-9) A](https://img.qammunity.org/2021/formulas/physics/college/l98xumsh5l1y8u24wou3ooutjstg81tt1e.png)
or, = 19.14 nA
Thus, we can conclude that the average current through the cell membrane is 19.14 nA.