Question

A 65-cm segment of conducting wire carries a current of 0.35 A. The wire is placed in a uniform magnetic field that has a magnitude of 1.24 T. What is the angle between the wire segment and the magnetic field if the force on the wire is 0.26 N

Answer 1

67.17°

Step-by-step explanation:

From the question,

F = BILsinФ............. Equation 1

Where F = force on the wire, B = magnetic field, I = current carried by the wire, L = length of the wire, Ф = angle between the wire segment and the magnetic field.

make Ф the subject of the equation

Ф =sin⁻¹ (F/BIL)............... Equation 2

Given; F = 0.26 N, B = 1.24, I = 0.35 A, L = 65 cm = 0.65 m

Substitute into equation 2

Ф = sin⁻¹[0.26/(1.24×0.35×0.65)]

Ф = sin⁻¹(0.26/0.2821)

Ф = sin⁻¹(0.9217)

Ф = 67.17°

Answer 2

Answer: The angle between the wire segment and the magnetic field 66.42°

Step-by-step explanation:

Please see the attachment below