Answer:
Step-by-step explanation:
If the initial current is i,
The energy delivered by the heater is given as
Hi=i²Rt
Then, when the current is double
So the new current is 2i
So the heat delivered will be
Hn=(2i)²Rt
Hn=4i²Rt
Hn=4•i²Rt , i²Rt =Hi
Hn=4•Hi
Notice that the resistance of the heater doesn't change.
And the time will not change since we are considering the same time intervals (t)
Conclusion, it is notice that the amount of heat delivered by the heater when the current was double, increase the heat delivered by a factor of 4.
So the correct answer is C