Final answer:
The probability of the sum being seven when at least one die is a six is 1/11, while the probability is 2/11 when at least one die is a five.
Step-by-step explanation:
The problem concerns the calculation of conditional probabilities when rolling a pair of dice. In part a), we are given that at least one die is a six, and we need to find the probability that the sum is seven. In part b), we are given at least one die is a five, and we need to find the probability that the sum is seven.
Part a)
If at least one die is a six, the possible outcomes are (6,1), (6,2), (6,3), (6,4), (6,5), (6,6), (1,6), (2,6), (3,6), (4,6), and (5,6), for a total of 11 outcomes. Only one of these, (6,1), results in a sum of seven. Therefore, the probability of the sum being seven is 1/11.
Part b)
If at least one die is a five, the possible outcomes are (5,1), (5,2), (5,3), (5,4), (5,6), (5,5), (1,5), (2,5), (3,5), (4,5), and (6,5), for a total of 11 outcomes. Two of these, (5,2) and (2,5), result in a sum of seven. Therefore, the probability of the sum being seven is 2/11.