Answer:
the velocity of the jet relative to the air as a vector in component form = (-272.3î + 525.7j) miles per hour
Explanation:
The velocity of the jet with respect to the air is described to have a magnitude of 580 miles per hour with a bearing of 332°.
Converting the bearing to the angle the velocity vector makes with the positive x-axis in the anti-clockwise direction, we have
θ = 360° - 332° + 90 = 118°
The bearing and the angle converted is shown in the attached image.
Velocity vector of the jet's speed relative to air is given as
Magnitude [(cos θ)î + (sin θ)j] = (580cos 118°)î + (580sin 118°)j = (-272.3î + 525.7j) miles per hour