Answer:
Part a: The value of Y_A and Y_B are
and
respectively.
Part b: Y_A and Y_B are given as
and
respectively for maximization of Y_B
Part c: The condition for the Pareto efficient allocation is Y_A=Y_B
As the value of Y_A and Y_B are not equal in part 2 thus the condition is not Pareto efficient
Step-by-step explanation:
Part a
For the value of the utility function is given as
![\bar{u}_A=xY_A\\Y_A=\frac{\bar{u}_A}{x}](https://img.qammunity.org/2021/formulas/business/college/f5mdhv1p6pe2188j7egzkh6l9k2gzq5t6g.png)
Also the YB is given as
![Y_A+Y_B=100-x\\Y_B=100-x-Y_A\\Y_B=100-x-\frac{\bar{u}_A}{x}](https://img.qammunity.org/2021/formulas/business/college/3ypzojtohbjentdmxkrxjkszw7msa3pc67.png)
So the value of Y_A and Y_B are
and
respectively.
Part b:
Now
![\bar{u}_B=xY_B\\\bar{u}_B=x(100-x-\frac{\bar{u}_A}{x})\\\bar{u}_B=100x-x^2-\bar{u}_A](https://img.qammunity.org/2021/formulas/business/college/zdqwd2vlvrhg79w085tbv6tj68lp8mbc91.png)
For the maximization
![\frac{\partial \bar{u}_B}{\partial x}=0\\\frac{\partial (100x-x^2-\bar{u}_A)}{\partial x}=0\\100-2x=0\\x=100/2\\x=50](https://img.qammunity.org/2021/formulas/business/college/727tdnlwi171uxlconau2cjdsjb5vd1adv.png)
From question 1 Y_A and Y_B are given as
and
respectively for maximization of Y_B
Part c:
At the Pareto efficient allocation
![(Mu_X)/(Mu_(Y_A))=(Mu_X)/(Mu_(Y_B))](https://img.qammunity.org/2021/formulas/business/college/s95o6a105rp12132l8gvhp6kydpt85wdu5.png)
This is simplified to
![(Y_A)/(x)=(Y_B)/(x)\\Y_A=Y_B](https://img.qammunity.org/2021/formulas/business/college/zn4azuf9ogqsmn0mov2no5ebw6kt1u2wgk.png)
The condition for the Pareto efficient allocation is YA=YB
As the value of YA and YB are not equal in part 2 thus the condition is not Pareto efficient