Question

A uniform magnetic field passes through a horizontal circular wire loop at an angle 15.1 ° from the normal to the plane of the loop. The magnitude of the magnetic field is 4.35 T , and the radius of the wire loop is 0.280 m . Find the magnetic flux Φ through the loop.

Answer 1

Magnetic flux through the loop is 1.03 T m²

Step-by-step explanation:

Given:

Magnetic field, B = 4.35 T

Radius of the circular loop, r = 0.280 m

Angle between circular loop and magnetic field, θ = 15.1⁰

Magnetic flux is determine by the relation:

`\Phi = BA\cos \theta` ....(1)

Here A represents area of the circular loop.

Area of circular loop, A = πr²

Hence, the equation (1) becomes:

`\Phi=B\pi r^(2) \cos \theta`

Substitute the suitable values in the above equation.

`\Phi=4.35*\pi (0.28)^(2) \cos 15.1`

`\Phi` = 1.03 T m²