Question

find the total surface area of a cylindrical candle with a diameter of 4 in and a height of 2.5 inch round to the nearest tenth

Answer 1



Explanation:

A=
`\pi r^(2)`

A=3.14*2*2*

A=12.56

A=25.12in

+

A=l*w

A=4*2.5

A=10in

TSA=35.1
`in^(2)`