Answer : The energy needed is,
![7.55* 10^(-3)kJ](https://img.qammunity.org/2021/formulas/chemistry/high-school/qsi8f1ruey297dcbc0n6b0lvsd6ae3pnr2.png)
Explanation :
Formula used :
![q=m* c* (T_(final)-T_(initial))](https://img.qammunity.org/2021/formulas/chemistry/high-school/ty5nz1y0bmvdegzf8fct5erm1xses7ig7n.png)
where,
q = heat needed = ?
m = mass = 7.70 g
c = specific heat =
![0.140J/g^oC](https://img.qammunity.org/2021/formulas/chemistry/high-school/i6uzsvgvk21gpxxtg14d7qler2j75rseyu.png)
= final temperature =
![58^oC](https://img.qammunity.org/2021/formulas/chemistry/high-school/w6ld3kh2thd7q84dh2l93znd1y4wamv8ed.png)
= initial temperature =
![51^oC](https://img.qammunity.org/2021/formulas/chemistry/high-school/em68jyf8t1paxenhypsw4r6m36mc7fz0nj.png)
Now put all the given values in the above formula, we get:
![q=7.70g* 0.140J/g^oC* (58-51)^oC](https://img.qammunity.org/2021/formulas/chemistry/high-school/jtwqtrmfhwo5xzp1trgeifdujv046xl7qd.png)
![q=7.546J=7.55* 10^(-3)kJ](https://img.qammunity.org/2021/formulas/chemistry/high-school/voq4ly0uz7k566xs9kxc2yvjbdw3v58via.png)
Thus, the energy needed is,
![7.55* 10^(-3)kJ](https://img.qammunity.org/2021/formulas/chemistry/high-school/qsi8f1ruey297dcbc0n6b0lvsd6ae3pnr2.png)