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A particular baseball diamond is actually a square with 7575​-foot sides. What is the distance from home plate to second​ base? Express the answer in simplified radical form. Then find a decimal approximation.

User Stu Gla
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1 Answer

3 votes

Answer:


75√(2)\approx 106.07 feet.

Explanation:

Please find the attachment.

We have been that a particular baseball diamond is actually a square with 75-foot sides.

We can see that distance from home plate to second​ base would be equal to hypotenuse with each leg of 75-ft.

We will use Pythagoras theorem to find the distance x as:


x^2=75^2+75^2


x^2=2(75^2)

Now, we will take positive square root of both sides as:


√(x^2)=√(2(75^2))


x=75√(2)


x=106.066017\approx 106.07

Therefore, the exact distance from home plate to second​ base is
75√(2) feet or approximately 106.07 feet.

A particular baseball diamond is actually a square with 7575​-foot sides. What is-example-1
User Tomtomtom
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