Answer: point - slope form
y-3=2(x-1)
Explanation:
Step 1:-
The equation of the line that passes through the point
and having slope 'm' is
![(y-y_(1)) = m(x-x_(1) )](https://img.qammunity.org/2021/formulas/mathematics/high-school/hlyfw1kqd69kbfy9eo5n3zp3lh2qny4x0q.png)
Given slope m= 2 and the point is
= (1,3)
The equation of the line that passes through the point
and having slope m=2 is
![(y-3) = 2(x-1 )](https://img.qammunity.org/2021/formulas/mathematics/high-school/wksrha7gerim57mf3n0vukqiw8cl087p40.png)
![y-3=2x-2](https://img.qammunity.org/2021/formulas/mathematics/high-school/sel3ukeiv0xluxefqertq1ibrcxtybpezw.png)
on simplification ,we get
![2x-y=-2+3](https://img.qammunity.org/2021/formulas/mathematics/high-school/x2xt0wt9bn114f59n84763nfk2ciavqmdy.png)
2x-y=1
The equation of the straight line is 2x-y-1=0