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How to solve (3p⁴ + 2q⁴)²​

User Mcbeav
by
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2 Answers

9 votes

We know the identity

  • (a+b)²=a²+b²+2ab

So


\\ \rm\Rrightarrow (3p^4+2q^4)^2


\\ \rm\Rrightarrow (3p^4)^2+(2q^4)^2+2(3p^4)(2q^4)


\\ \rm\Rrightarrow 9p^8+4q^8+12p^4q^4

Done

User Rajbir
by
4.6k points
4 votes

Answer:

9p⁸ + 12p⁴q⁴ + 4q⁸

Explanation:

(3p⁴ + 2q⁴)²​ ⇒ The square of (3p⁴ + 2q⁴)

Squares are such bases that multiply itself two times.

⇒ (3p⁴ + 2q⁴)(3p⁴ + 2q⁴)

Simplifying the expression using (a + b)(a + b) = (a x a) + (ab) + (ab) + (b²)

⇒ (9p⁸ + 6p⁴q⁴ + 6p⁴q⁴ + 4q⁸)

⇒ (9p⁸ + 12p⁴q⁴ + 4q⁸) = 9p⁸ + 12p⁴q⁴ + 4q⁸

User Bartburkhardt
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