Answer:
a = r√(w⁴ + (alpha)²)
Step-by-step explanation:
let w be the magnitude of angular velocity
r = radius
v = velocity = wr
angular acceleration, ā = v²/r = (wr)²/r = w²r
Also,
â = dv/dt = rdw/dt
given : alpha = dw/dt
hence, â = (alpha)r
the resultant acceleration, a, by Pythagoras is given as
a = √( â² + ā²) = √(r²w⁴ + r²(alpha)²)
simplifying,
a = √r²(w⁴ + (alpha)²)
a = r√(w⁴ + (alpha)²)