Answer:
This claim is not reasonable.
Step-by-step explanation:
In order to calculate the power required by the pump assuming 100% efficiency we use formula:
P = Qρgh
where,
P = power
Q = volume flow rate = 50 L/s = 0.05 m³/s
ρ = density of water = 1000 kg/m³
g = 9.8 m/s²
h = height = 30 m
Therefore,
P = (0.05 m³/s)(1000 kg/m³)(9.8 m/s²)(30 m)
P = 14700 W = 14.7 KW
Since, the power required by the the pump in case of 100% efficiency is 14.7 KW. It must require more power than this in actual, because the efficiency can never be 100%, due to losses.
Therefore, this claim is not at all reasonable, that the pump of 2 KW can perform this task.