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Microwave ovens emit microwave energy with a wavelength of 12.7 cm. What is the energy of exactly one photon of this microwave radiation? socratic.org

User RiskTech
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Answer:

The energy of one photon of this microwave radiation is
1.56* 10^(-24)\ J.

Step-by-step explanation:

Given that,

Wavelength of the microwave,
\lambda=12.7\ cm=12.7* 10^(-2)\ m

We need to find the energy of exactly one photon of this microwave radiation. We know that the energy of a photon is given by the formula as :


E=(nhc)/(\lambda)\\\\E=(1* 6.63* 10^(-34)* 3* 10^8)/(12.7* 10^(-2))\\\\E=1.56* 10^(-24)\ J

So, the energy of one photon of this microwave radiation is
1.56* 10^(-24)\ J. Hence, this is the required solution.

User Youka
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