Question

A student used 6.34 x 10-3 kg of t-butanol in the synthesis of BHT. Assuming no other substances are limiting, how many grams of BHT can be formed? 9.42 g BHT 6.11 g BHT 18.8 g BHT 12.9 g BHT

Answer 1

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Step-by-step explanation:

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Answer 2

Answer: The mass of BHT that can be formed is 18.8 grams

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` .....(1)

Given mass of t-butanol =
`6.34* 10^(-3)kg=6.34g` (Conversion factor: 1 kg = 1000 g)

Molar mass of t-butanol = 74 g/mol

Putting values in equation 1, we get:

`\text{Moles of t-butanol}=(6.34g)/(74g/mol)=0.086mol`

The chemical equation for the formation of BHT from t-butanol follows:

`\text{t-butanol + p-cresol}\rightarrow \text{BHT}`

By Stoichiometry of the reaction:

1 mole of t-butanol produces 1 mole of BHT

So, 0.086 moles of t-butanol will produce =
`(1)/(1)* 0.086=0.086mol` of BHT

Now, calculating the mass of BHT from equation 1, we get:

Molar mass of BHT = 220 g/mol

Moles of BHT = 0.086 moles

Putting values in equation 1, we get:

`0.086mol=\frac{\text{Mass of BHT}}{220g/mol}\\\\\text{Mass of BHT}=(0.086mol* 220g/mol)=18.8g`

Hence, the mass of BHT that can be formed is 18.8 grams