Answer:
a. P₂O₅
b .KH₂PO₄
Step-by-step explanation:
In order to determine empirical formula of a compound, we divide the percent (as an integer number of mass) by the molar mass of the element and afterwards we divide, by the lowest value.
Centesimal composition by percent means the mass of the element in 100 g of compound
a. 43.6 g of P / Molar mass P → 43.6 g/ 30.97 g/mol = 1.41 moles
56.4 g of O / Molar mass O → 56.4 g / 16 g/mol = 3.52 moles
So, 1.41 moles of P / 1.41 = 1 mol of P
3.52 moles of O / 1.41 = 2.5 moles of O
We finally have 1 mol of P and 2.5 moles of O, bu we can't have rational numbers, so to have an integer we multiply by 2 (x2)
1 mol of P . 2 = 2 P
2.5 moles of O . 2 = 5 O
Empirical formula is P₂O₅
b. 28.74 g / 39.1 g/mol = 0.735 moles K
1.5 g / 1g/mol = 1.5 moles H
22.8 g / 30.97 g/mol = 0.736 moles P
47 g / 16 g/mol = 2.93 moles O
0.735 moles K / 0.735 = 1 mol K
1.5 moles H / 0.735 = 2 mol H
0.736 moles P / 0.735 = 1 mol P
2.93 moles O / 0.735 = 4 mol O
Empirical formula is KH₂PO₄