Question

It took a crew 9 h 36 min to row 8 km upstream and back again. If the rate of flow of the stream was 2 km/h, what was the rowing speed of the crew in still water?

Answer 1

3 km/h

Step-by-step explanation:

Let's call the rowing speed in still water x, in km/h.

Rowing speed in upstream is: x - 2 km/h

Rowing speed in downstream is: x + 2 km/h

It took a crew 9 h 36 min ( = 9 3/5 = 48/5) to row 8 km upstream and back again. Therefore:

8/(x - 2) + 8/(x + 2) = 48/5 (notice that: time = distance/speed)

Multiplying by x² - 2², which is equivalent to (x-2)*(x+2)

8*(x+2) + 8*(x-2) = (48/5)*(x² - 4)

Dividing by 8

(x+2) + (x-2) = (6/5)*(x² - 4)

2*x = (6/5)*x² - 24/5

0 = (6/5)*x² - 2*x - 24/5

Using quadratic formula

`x = (2 \pm √((-2)^2 - 4(6/5)(-24/5)))/(2(6/5))`

`x = (2 \pm 5.2)/(2.4)`

`x_1 = (2 + 5.2)/(2.4)`

`x_1 = 3`

`x_2 = (2 - 5.2)/(2.4)`

`x_2 = -1\; 1/3`

A negative result has no sense, therefore the rowing speed in still water was 3 km/h