Known :
V1 = 10 L
T1 = 27°C
P1 = 12 atm
P2 = 3 atm
Solution :
Work done in the process
W = P1 • V1 ln (P1 / P2)
W = (12 atm) • (10 L) ln (12 / 3)
W = 166.35 L • atm
W = 168.55 kJ
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