Question

The magnetic dipole moment of Earth is 8.00 ✕ 1022 J/T. Assume that this is produced by charges flowing in Earth's molten outer core. If the radius of their circular path is 2350 km, calculate the current they produce.

Answer 1

Therefore,

Current produce is

`i=4.61* 10^(9)\ Ampere`

Step-by-step explanation:

Given:

Magnetic dipole moment of Earth,

`\mu=8* 10^(22)\ J/T`

Radius = r = 2350 km = 2.35 × 10⁶ m

To Find:

Current, i =?

Solution:

Magnetic Dipole Moment:

A magnetic moment is a quantity that represents the magnetic strength and orientation of a magnet or any other object that produces a magnetic field.

Magnetic dipole moments have dimensions of current times area.

It is given by,

`\mu=i* Area`

Where,

`\mu` = Magnetic dipole moments

i = Current

A = area =
`\pr r^(2)`

Substituting the values we get

`i=(\mu)/(\pi r^(2))=(8* 10^(22))/(3.14* (2.35* 10^(6))^(2))`

`i=(8* 10^(22))/(17.34* 10^(12))=4.61* 10^(9)\ Ampere`

Therefore,

Current produce is

`i=4.61* 10^(9)\ Ampere`