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The volume of a sample of oxygen is 200.0 mL when the pressure is 3.000 atm and the temperature is 37.0 oC. What is the new temperature if the volume increases to 400.0 mL and the pressure decreases to 2.000 atm

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Final answer:

To find the new temperature when the volume and pressure change, we can use the combined gas law equation. By plugging in the initial values and rearranging the equation, we can calculate the new temperature. In this case, the new temperature is approximately 390.88 degrees Kelvin.

Step-by-step explanation:

To solve this problem, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature. The combined gas law equation is:

P1V1/T1 = P2V2/T2

We can plug in the initial values (P1 = 3.000 atm, V1 = 200.0 mL, and T1 = 37.0 °C) and solve for T2, which represents the new temperature when the volume increases to 400.0 mL and the pressure decreases to 2.000 atm.

By rearranging the equation and plugging in the values, we can find that T2 = 273.15 + (37.0 + 273.15) * (2.000 * 400.0) / (3.000 * 200.0) = 390.88 K. Therefore, the new temperature is approximately 390.88 degrees Kelvin.

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